I need some help figuring out this questions please! Q: The data in the table ar

Question

I need some help figuring out this questions please!

Q: The data in the table are for the reaction of NO andO2 at 660K.

[NO]
[O2]       [rate of apperrance of NO2
0.01 0.01                  2.5 x 10-5
0.02 0.01                 1.0 x 10 -4
0.01 0.02                  5.0 x 10-5

Q: At the instant when NO is reacting at the rate 1.0 x10-4 mol/L*s, what is the rate at which O2 isreacting and NO2 is forming?

Any help figuring this problem out would be much appreciated!!!

[NO]
[O2]       [rate of apperrance of NO2
0.01 0.01                  2.5 x 10-5
0.02 0.01                 1.0 x 10 -4
0.01 0.02                  5.0 x 10-5

Explanation / Answer

Chemical equation:                                       2 NO + O2 -------------> 2 NO2 Rate = -1/2 d[NO]/dt   = -d[O2 ] / dt = + 1/2 d[NO2] / dt Given that d[NO]/dt   = 1.0 x 10-4mol/L*s      Then d[O2 ] /dt    = - ( - 1/2 (  1.0 x10-4 mol/L*s)                                  = 5.0 x 10-5 mol/L*s              d[NO2] / dt = 2 * 5.0 x10-5 mol/L*s                                   =1.0 x 10-4 mol/L*s                                             Rate = -1/2 d[NO]/dt   = -d[O2 ] / dt = + 1/2 d[NO2] / dt Given that d[NO]/dt   = 1.0 x 10-4mol/L*s      Then d[O2 ] /dt    = - ( - 1/2 (  1.0 x10-4 mol/L*s)                                  = 5.0 x 10-5 mol/L*s              d[NO2] / dt = 2 * 5.0 x10-5 mol/L*s                                   =1.0 x 10-4 mol/L*s                                            

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.