Calculate the enthalpy change for the reactions NO (g) + O (g) --> NO 2 (g) from

Question

Calculate the enthalpy change for the reactions NO (g) + O (g) --> NO2 (g) from the following data: NO (g) + O3 (g) --> NO2 (g) +O2(g)                      H= -198.9 kJ O3 (g) --> 1.5 O2(g)                                               H= -142.3 kJ O2 (g) -->2O(g)                                                      H= 495.0 kJ Calculate the enthalpy change for the reactions NO (g) + O (g) --> NO2 (g) from the following data: NO (g) + O3 (g) --> NO2 (g) +O2(g)                      H= -198.9 kJ O3 (g) --> 1.5 O2(g)                                               H= -142.3 kJ O2 (g) -->2O(g)                                                      H= 495.0 kJ

Explanation / Answer

We need to manipulate the three given reactions until we get afinal result of the reaction we are looking for. NO + O3 --> NO2 +O2              H = -198.9kJ                    leave this equation as is 1.5 O2 -->O3                              H = +142.3 kJ                   reverse the equation. also reverse the sign of H NO + 0.5 O2 -->NO2                 H = -56.6kJ                      this is the intermediate reaction we get byadding 0.5 O2 +O                                   H = 247.5kJ                     divide the given equation by 2. divide H by2 NO + O -->NO2                         H = 190.9kJ                     this is the final equation we are lookingfor.

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