A chemist does a reaction analysis on the following reaction: 2CO (g) + O2 (g) -

Question

A chemist does a reaction analysis on the following reaction:

2CO (g) + O2 (g) --> 2CO2 (g)

She collects the following data:

Trial Initial Concentration CO (M)
Initial Concentration O2 (M)
Instantaneous Reaction Rate (M/s)
1 0.150 0.150 0.113 2 0.300 0.150 0.226 3 0.300 0.300 0.904
What is the rate equation for this reaction?

Reaction Rate (M/s)
Trial Initial Concentration CO (M)
Initial Concentration O2 (M)
Instantaneous Reaction Rate (M/s)
1 0.150 0.150 0.113 2 0.300 0.150 0.226 3 0.300 0.300 0.904

Explanation / Answer

Note that when [CO] is doubled (step 1 to step 2), the reactionrate goes up by a factor of 2. This suggests a linear relationship for CO. Then, when the [O2] is doubled (step 2 to step 3), the reactionrate goes up by a factor of 4, which is 2 squared. This suggests a squaring relationship for O2. So the rate equation should be: Rate = [CO][O2]2 Edit: anything inside brackets [ ] means concentration

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