To understand how reactions at equilibrium respond to changes in conditions, inc

Question

To understand how reactions at equilibrium respond to changes in conditions, including volume changes and addition of reactants or products. Equilibrium equations can be used to determine what will happen to a system at equilibrium if certain conditions are changed (e.g., the addition of a reactant or product or-in the case of gaseous reactions-a volume change). For example, given the reaction 1/8 S8(S) + O2(g) So2(g) what will happen to the system if more SO2(g) is added so that the concentration of SO2(g) is doubled? The equilibrium equation is given by Equilibrium equations do not include expressions for any pure solids or liquids that may be involved in the reaction. This is because at any given temperature their concentration is constant, and these values are by convention included in the value of the equilibrium constant. Since the value of K remains constant for the reaction at any given temperature, if the value of [SO2] is doubled, then the value of [O2] must also double to return the system to equilibrium. For the decomposition of A to B and C, A(s) B(g) + C(g) now will the reaction respond to each of the following changes at equilibrium? Drag the appropriate items to their respective bins. For the reaction of A and B forming C, A(g) + B(s) 2C(g) how will the reaction respond to each of the following changes at equilibrium? Drag the appropriate items to their respective bins.

Explanation / Answer

Part A Double products and volume = no shift The products would want to shift right but the volume increaseshifts left. Double products = left shift The products want to go to equilibruim so they shiftleft. Double [b] and halve [c] = no shift The products remain in equilibrium. Double concentrations, quad volume = right shift They shift to the right because doubling everything it wantsto shift left but the volume increase will move to the sidewith more moles of gas. Add A = no shift Double volume = right shift Part B Halve C = right shift Halve A = left shift Double A and C = left shift A and C are not proportional! Double A = right shift Quad B = no shift I am gonig to PM you an explanation on how to do theseproblems that I posted for someone else yesterday.

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