Very few chemical reactions go to completion. Instead, most reach a state called
ID: 683562 • Letter: V
Question
Very few chemical reactions go to completion. Instead, most reach a state called chemical equilibrium in which both products and reactants are present. The concentrations of reactants and products can be predicted using the equilibrium constant, Kc, which is a mathematical expression based on the chemical equation. For example, in the reaction aA + bB cC + dD where a, b, c, and d are the stoichiometric coefficients, the equilibrium constant is where [A], [B], [C], and [D] are the equilibrium concentrations. If the reaction is not at equilibrium, the quantity can still be calculated, but it is called the reaction quotient, Qc, instead of the equilibrium constant, Kc. A mixture initially contains A, B, and C in the following concentrations: [A] = 0.550 M, [B] = 1.40 M, and [C] = 0.350 M. The following reaction occurs and equilibrium is established: A + 2B C At equilibrium. [A] = 0.350 M and [C] = 0.550 M. Calculate the value of the equilibrium constant, Kc. Express your answer numerically.Explanation / Answer
We Know that : The given Reaction is ; A+ 2B <-----> C I : 0.55 M 1.40 M 0.350 M C : -x - 2x + x E : 0.350M 0.550 M Fromthe equilibrium concentrations we can compute the changeoccured 0.350 M + x = 0.550 M x = 0.550 M - 0.350 M = 0.20 M equilibriumconcentration of B = 1.40 - 2 ( 0.20 M) = 1.0 M Kc = [ C ] / [ A ] [ B ]2 = [ 0.550 M ] / [ 0.350 M ] [ 1.0 M]2 = 1.5714 = 1.5714Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.