For reaction H2 (g0) + F2 (g) <---> 2HF k= 1.15 x 10 2 . In experiment 3.000 mol

Question

For reaction H2 (g0) + F2 (g) <---> 2HF   k= 1.15 x 102. In experiment 3.000 molof each component was added to 1.5000 L flask. Calculate the equil.con. of all species. I understand how to do the ice table however my basic algebrais killing me. Can someone please explain step by step exactly howthey calculated the x value please. K = 1.15 x 102 = (2.00 +2x)2
                             (2.00-x)2               I know you have to take the square root of the K value, which givesu K = 107.23 = 2.00 +2x
                     2.00 - x       maysomeone please tell me step by step how exactly it is you calculatethe x value and show it to me mathmatically. Thank you so muchlifesaver!!! I appreciate it! For reaction H2 (g0) + F2 (g) <---> 2HF   k= 1.15 x 102. In experiment 3.000 molof each component was added to 1.5000 L flask. Calculate the equil.con. of all species. I understand how to do the ice table however my basic algebrais killing me. Can someone please explain step by step exactly howthey calculated the x value please. K = 1.15 x 102 = (2.00 +2x)2
                             (2.00-x)2               I know you have to take the square root of the K value, which givesu K = 107.23 = 2.00 +2x
                     2.00 - x       maysomeone please tell me step by step how exactly it is you calculatethe x value and show it to me mathmatically. Thank you so muchlifesaver!!! I appreciate it! K = 107.23 = 2.00 +2x
                     2.00 - x       maysomeone please tell me step by step how exactly it is you calculatethe x value and show it to me mathmatically. Thank you so muchlifesaver!!! I appreciate it!

Explanation / Answer

First off, the square root of 1.15 x 102 is10.355, not 107.23. Maybe that’s your problem.

Since everything has 3 significant figures, you only need do thecomputations to 3 figures.

                         10.4 = (2 + 2x ) / (2 –x)

          (2– x) 10.4      = (2 + 2x)

         20.8 –10.4x        = 2 + 2x

         20.8 –10.4 x – 2 =        2x

      

          18.8                  = 2x + 10.4x

           

          18.8                  =12.4 x

           18.8 / 12.4       = x

           1.52                 = x   (moles per liter)

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