Given the following free energies of formation, calculate Kpfor the following re

Question

Given the following free energies of formation, calculate Kpfor the following reaction below at 298 K. SO2(g) + NO2(g) --->SO3(g) + NO(g)                             Gof (kJ/mol) SO2(g)                     -300.4 kJ/mol SO3(g)                     -370.4 kJ/mol NO(g)                         86.7 kJ/mol NO2(g)                        51.8kJ/mol Given the following free energies of formation, calculate Kpfor the following reaction below at 298 K. SO2(g) + NO2(g) --->SO3(g) + NO(g)                             Gof (kJ/mol) SO2(g)                     -300.4 kJ/mol SO3(g)                     -370.4 kJ/mol NO(g)                         86.7 kJ/mol NO2(g)                        51.8kJ/mol SO2(g)                     -300.4 kJ/mol SO3(g)                     -370.4 kJ/mol NO(g)                         86.7 kJ/mol NO2(g)                        51.8kJ/mol

Explanation / Answer

we know that G= - RTlnK where k is the rate of constant as here all the reactants andproducts are gaseous so n=0 now G total = G(product-reactant)                      =86.7-370.4-51.8+300.4 KJ/mol                      = -35.1 KJ/mol so k= e-G/RT       = 1.01426 (ans) its alright now

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