This is the question. Mothballs are composed primarily of the hydrocarbonnaphtha
ID: 683718 • Letter: T
Question
This is the question.Mothballs are composed primarily of the hydrocarbonnaphthalene (C10H8). When 1.025 g of naphthalene is burned ina bomb calorimeter, the temperature rises from 24.25 degrees C to32.33 degrees C. Find the change in E rxn for the combustionof naphthalene. The heat capacity of the calorimeter,determined in separate experiment, is 5.11 kJ/degrees C.
Can you please give me the steps so I can really understand? Thank you so much!
Mothballs are composed primarily of the hydrocarbonnaphthalene (C10H8). When 1.025 g of naphthalene is burned ina bomb calorimeter, the temperature rises from 24.25 degrees C to32.33 degrees C. Find the change in E rxn for the combustionof naphthalene. The heat capacity of the calorimeter,determined in separate experiment, is 5.11 kJ/degrees C.
Can you please give me the steps so I can really understand? Thank you so much!
Explanation / Answer
Mothballs arecomposed primarily of the hydrocarbon naphthalene(C10H8). When 1.025 g of naphthalene is burned in a bomb calorimeter, thetemp rises from 24.25 degrees C to 32.33 degrees C. Find the change in Erxn for the combustion of naphthalene. The heat capacity of thecalorimeter, determined in separate experiment, is 5.11 kJ/degreesC {Mass Of Naphthalene Burned} = m = 1.025 g {Molar Mass Of Naphthalene} = Mm = 128.17052 g/mol {Moles Of Naphthalene Burned} = M = = m/Mm = (1.025)/(128.17052) = 0.0079971 moles {Temperature Change Of Calorimeter} = T = = {Final Temp} - {Initial Temp} = (32.33) -(24.25) = 8.08 degC {Heat Capacity Of Calorimeter} = C = 5.11kJ/degC {Energy Absorbed By Calorimeter} = Q = = C*T = (5.11 kJ/degC)*(8.08 degC) = 41.2888 kJ The energy "Q" absorbed by the calorimeter is produced by the chemical reaction and is used to compute the Reaction Energy (Erxn): {Reaction Energy} = Erxn = = Q/M = (41.2888 kJ)/(0.0079971 moles) = 5163 kJ/mole .
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