Hello all, I am sooo confused and need your help! I will for sure ratelifesaver

Question

Hello all, I am sooo confused and need your help! I will for sure ratelifesaver for someone who can explain what happened in clear cutsteps. I need to understand this as soon as possible. Thanks inadvance :) Question: What is the enthalpy change in the followingreaction? Compound A. Ch4 (gas) has heat of formation of -75kj/mol Compound B. Co2 (gas) has heat .... -394 kj/mol Compound C. H20 (liquid) ..... ....... -286 kj/mol The reaction is: Ch4 + 2O2 ---> Co2 + H20 Answer is -891 kj. How did this happen? Hello all, I am sooo confused and need your help! I will for sure ratelifesaver for someone who can explain what happened in clear cutsteps. I need to understand this as soon as possible. Thanks inadvance :) Question: What is the enthalpy change in the followingreaction? Compound A. Ch4 (gas) has heat of formation of -75kj/mol Compound B. Co2 (gas) has heat .... -394 kj/mol Compound C. H20 (liquid) ..... ....... -286 kj/mol The reaction is: Ch4 + 2O2 ---> Co2 + H20 Answer is -891 kj. How did this happen?

Explanation / Answer

CH4 + 2O2 ---> CO2 + 2H20 Heat of formation of CH4 (gas) is, H CH4= -75 kj/mol Heat of formation of CO2 (gas) is,H CO2 = -394 kj/mol Heat of formation of H2O(gas) is,H H2O = -286 kj/mol H = H products - Hreactants       =H CO2 + 2 *H H2O - ( H CH4 + 2 * H O2 )       = -394 + 2 ( -286 ) - ( -75 + 2( 0 ) )       = - 891 KJ / mol       =H CO2 + 2 *H H2O - ( H CH4 + 2 * H O2 )       = -394 + 2 ( -286 ) - ( -75 + 2( 0 ) )       = - 891 KJ / mol

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