Using the following bond energies, calculate the molar heat ofhydrogeneration, H
ID: 684803 • Letter: U
Question
Using the following bond energies, calculate the molar heat ofhydrogeneration, Hhydrogeneration, for theconversion of C2H2 toC2H6. CH = CH(g) + 2H2(g) -->CH3CH3(g) Bond BondStrength (kJ/mol) C-C 348 CtriplebondC 839 C-H 411 H-H 432 Using the following bond energies, calculate the molar heat ofhydrogeneration, Hhydrogeneration, for theconversion of C2H2 toC2H6. CH = CH(g) + 2H2(g) -->CH3CH3(g) Bond BondStrength (kJ/mol) C-C 348 CtriplebondC 839 C-H 411 H-H 432Explanation / Answer
CH triple bond CH(g) + 2H2(g) -->CH3CH3(g) The above reaction involves i) breaking of one Ctriple bond C & two H-H bonds ii ) formation of one C-C bond & four C-H bonds Endothermic reactions are taking +ve sign & exothermicreactions are taking -ve sign So, enthalphy change for breaking(endothermic) of i) one Ctriple bond C : H = 839 KJ/ mol ii ) two H - H bonds : H = 2*432 KJ/mol =864 KJ/ mol enthalphy change for formation ( exothermic ) ofiii) one C - C : H = -348 KJ/ mol iv ) four C - H bonds : H = -4*411 KJ/mol = -1644 KJ/ mol On adding i) to iv ) we get H = 839 + 864 -348 - 1644 = -289 KJ/mol iv ) four C - H bonds : H = -4*411 KJ/mol = -1644 KJ/ mol On adding i) to iv ) we get H = 839 + 864 -348 - 1644 = -289 KJ/molRelated Questions
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