balance: KMnO4 + CaC2O4+ H2SO4 ----> MnSO4+ K2SO4+ CaSO4+ CO2 +H2O KMnO4 + CaC2O
ID: 685205 • Letter: B
Question
balance:KMnO4 + CaC2O4+ H2SO4 ----> MnSO4+ K2SO4+ CaSO4+ CO2 +H2O
KMnO4 + CaC2O4+ H2SO4 ----> MnSO4+ K2SO4+ CaSO4+ CO2 +H2O
Explanation / Answer
C2O42- => CO2 C2O42- => 2CO2 C2O42- => 2CO2 +2e- C is +3in C2O4, but it is +4 in CO2. There are 2 C's on each side,so 2*(4-3) = 2 e- balance O's with H2O C2O42- => 2CO2 +2e- C2O42- is soluble form of CaC2O4 balance H's with H+ C2O42- => 2CO2 + 2e- next half reaction MnO4- => MnSO4 MnO4- => Mn2+ Mn2+ is soluble form of MnSO4, MnO4- is soluble form of KMnO4 Mn goes from +7 in MnO4- to +2 => need 5 electrons MnO4- + 5e- => Mn2+ add H2O to balance O's MnO4- + 5e- => Mn2+ + 4H2O add H+ to balance H's MnO4- + 5e- + 8H+ => Mn2+ +4H2O Add bolded equations. 2*[ MnO4- + 5e- + 8H+ => Mn2+ + 4H2O] 5* [C2O42- => 2CO2 + 2e-]--------------------------------------------------------- 2MnO4- + 10e- + 16 H+ + 5C2O4- => 2Mn2+ + 8 H2O + 10CO2 + 10e- 2MnO4- + 16 H+ + 5C2O4- => 2Mn2+ +8 H2O + 10CO2 add back K+, Ca2+, and SO42- 2KMnO4 + 8H2SO4 + 5CaC2O4 => 2MnSO4 + K2SO4 + 5CaSO4 +8H2O
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