NH 3 (g) reacts with NO gas to producewater (g) and N 2 gas. a.How many grams of

Question

NH3 (g) reacts with NO gas to producewater (g) and N2 gas. a.How many grams of N2 gas can be producedfrom 1.25 moles of NO? b.How many grams of NH3 are required toform 3.20 moles of water? c.If 0.865 g of water is formed, how many moles of NO arerequired? d.If you used 1.25 moles of NO and you actually produce 0.70moles of N2 gas, what is the theoretical yield? NH3 (g) reacts with NO gas to producewater (g) and N2 gas. a.How many grams of N2 gas can be producedfrom 1.25 moles of NO? b.How many grams of NH3 are required toform 3.20 moles of water? c.If 0.865 g of water is formed, how many moles of NO arerequired? d.If you used 1.25 moles of NO and you actually produce 0.70moles of N2 gas, what is the theoretical yield?

Explanation / Answer

4NH3 + 6NO >>> 6H20 +5 N2 is the balancedequation (a) 1.25 mol NO * 5 mol N2/ 6 mol NO * 28.02 g N2/ 1mol = 29.2 gN2 produced (b) 3.20 mol H2O * 4 mol NH3 / 6 mol H2O * 17.01 g NH3/ 1 molNH3 = 36.3 g NH3 required (C) 0.865 g H2O * 1 mol H2O/ 18.0 g H2O * 6 mol NO/ 6 mol H2O= 0.481 mol NO (d) 1.25 mol NO * 0.70 mol N2/ 6 mol NO = 0.146 mol N2 is thetheoretical yield

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