Find the fraction of the ethyl chloride thatdecomposes in 16 minutesat this temp

Question

Find the fraction of the ethyl chloride thatdecomposes in 16 minutesat this temperature. Express your answer using onesignificant figure. Find the temperature at which the rate of thereaction would be twice as fast. Express your answer using twosignificant figures. =

Explanation / Answer

k = A*exp(-E/RT) = (1.6e14 /s)*exp(-249e3 J/mol /8.314 J/mol-K *730 K ) k= 0.000243475597 = 2.4 e-4 s-1 b) [A]/[A0] = exp(-k*t) = exp(-2.4e-4 s-1 *16 min * 60 s/min) = 0.791570309 {[A0] - [A]}/[A0] = 1 - [A]/[A0] = 1 - 0.7915 = 0.218 =>21.8% c) (k1) = A*exp(-E/RT1) (k2) = A*exp(-E/RT2) k1/k2 = exp[(-E/R)*[1/T1 - 1/T2] ] ln(k1/k2) = (-E/R)*[1/T1 - 1/T2] 1/T1 - 1/T2 = -(R/E)*ln(k1/k2) 1/T1 + (R/E)*ln(k1/k2) = 1/T2 T2 = [1/T1 + (R/E)*ln(k1/k2)]-1 k2 = 2*k1T2 = [1/730K + (8.314 J/mol / 249 e3J/mol) *ln(1/2)]-1 T2 = 742.545326 = 743 K

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