aFeS 2 + bH 2 O + cO 2 ®dFe 2+ +eH + + fSO 4 2- Derive the coefficients a, b, c,

Question

aFeS2 + bH2O + cO2 ®dFe2+ +eH+ + fSO42- Derive the coefficients a, b, c, d, e, and f inreaction aFeS2 + bH2O + cO2 ®dFe2+ +eH+ + fSO42- Derive the coefficients a, b, c, d, e, and f inreaction Derive the coefficients a, b, c, d, e, and f inreaction

Explanation / Answer

aFeS2 + bH2O + cO2 ->dFe2+ +eH+ + fSO42- Let a = 1, then d = 1 (to conserve Fe atoms) FeS2 + bH2O + cO2 ->Fe2+ +eH+ + fSO42- balance S's. There are 2 S's on the left. So put 2 before SO42- FeS2 + bH2O + cO2 ->Fe2+ +eH+ + 2SO42- neutralized the right. Since there is a 2+ charge from Fe2+, and2*(2-) = -4 from the two SO42-, add 2H+ on the right FeS2 + bH2O + cO2 ->Fe2+ +2H+ + 2SO42- b = 1 to balance H FeS2 + H2O + cO2 ->Fe2+ +2H+ + 2SO42- There are 8 O's on the right and 1 on the left (H2O) and 2c fromO2. So put 7/2 for c FeS2 + H2O + (7/2)O2 ->Fe2+ +2H+ + 2SO42- fractional coefficients are not preferred; multiply both sides by2 2FeS2 + 2H2O + 7O2 ->2Fe2+ +4H+ + 4SO42-

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