1) a 3.70g sample of sodium is allowed to react completely with sulfur to form a
ID: 685929 • Letter: 1
Question
1) a 3.70g sample of sodium is allowed to react completely with sulfur to form a sulfide that weighs 6.30g. calculate the following: mass of sulfur, moles of sulfur, moles of sodium, ratio of atoms of sodium to sulfur, empirical formula of the compound.Explanation / Answer
The balanced chemical equation is 2Na + S ------> C 2moles 1mole 1 mole 2X22.99 g =45.98 g 32.07g 78.04g 3.70g X 6.30 g mass of sulfur(X) = (32.07/45.98) x 3.70 = 2.58066 g moles ofsulfur = mass of sulphur / atomicwt = 2.58066 g / 32.07 g =0.08046 moles moles of sodium = mass of sodium / atomicwt = 3.70 g /22.99 g =0.16094 moles ratio of atoms of sodium to sulfur = rato of moles =0.16094/0.08046 =1.996 ˜ 2 ===> 2:1 empirical formula = Na2S
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.