You are asked to prepare a .8500M solution of aluminumnitrate. You find that you

Question

You are asked to prepare a .8500M solution of aluminumnitrate. You find that you have only 50.00g of thesolid. a.) What is the maximum volume of solution that you canprepare? b.) How many milliliters of this prepared solution arerequired to furnish .5000 mol of aluminum nitrate to areaction You are asked to prepare a .8500M solution of aluminumnitrate. You find that you have only 50.00g of thesolid. a.) What is the maximum volume of solution that you canprepare? b.) How many milliliters of this prepared solution arerequired to furnish .5000 mol of aluminum nitrate to areaction

Explanation / Answer

molar mass of Al(NO3)3 is 213 g/mol a) 50g Al(NO3)3 * (1mol / 213g) = .235mol .85M = .85mol / 1L (1L / .85mol) * .235mol =.276L         which is yourmaximum volume

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