Boron and Sulfur form two different binary compunds. The firstcontains the mass

Question

Boron and Sulfur form two different binary compunds. The firstcontains the mass ratio, 0.2247gB/1.000gS and the second contains0.1348gB/1.000gS. If the formula of the first compund is multiple of B2S3 the formula of the secondcompund is a multiple of which of the formula below? BS2 BS3 B2S5 B2S7 B3S2 I actually know it is B2S5 but I can'tfigure out why. Thanks! Boron and Sulfur form two different binary compunds. The firstcontains the mass ratio, 0.2247gB/1.000gS and the second contains0.1348gB/1.000gS. If the formula of the first compund is multiple of B2S3 the formula of the secondcompund is a multiple of which of the formula below? BS2 BS3 B2S5 B2S7 B3S2 I actually know it is B2S5 but I can'tfigure out why. Thanks! I actually know it is B2S5 but I can'tfigure out why. Thanks!

Explanation / Answer

Molar mass of B is = 10.8 g Molar mass of S = 32.06 g For B2S3 , ratio of masses of B& S is = 2 * 10.8 / ( 3 * 32 .06 )                                                            = 0.2245 g B / 1.0000 g S For B2S5 , ratio of masses of B & Sis = 2 * 10.8 / ( 5 * 32 .06 )                                                            = 0.1347 g B / 1.0000 g S                                                            = 0.1347 g B / 1.0000 g S

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