Question: A 192-g peice of copper was heated to 100.0 o C in aboiling water bath

Question

Question: A 192-g peice of copper was heated to 100.0 oC in aboiling water bath and then put into a beaker containing 750.mlwater (density=1.00g/cm3)at 4.0oC. What isthe final temperature of the copper and water after they come tothermal equilibrium? I was half way through this problem then got stuck..Pleaseexplain and show each step on how you solved this problem. Thanksfor the help Question: A 192-g peice of copper was heated to 100.0 oC in aboiling water bath and then put into a beaker containing 750.mlwater (density=1.00g/cm3)at 4.0oC. What isthe final temperature of the copper and water after they come tothermal equilibrium? I was half way through this problem then got stuck..Pleaseexplain and show each step on how you solved this problem. Thanksfor the help

Explanation / Answer

Should be using this equition to solve this.. CwaterxMwater x T = -CcopperxMcopperxTcopper

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.