A standard solution of 0.154 M HCl is used to determine theconcentration of a Na

Question

A standard solution of 0.154 M HCl is used to determine theconcentration of a NaOH solution whose concentration is unknown. If33.5 mL of the acid solution are required to neutralize 25.0 mL ofthe base solution, the concentration of the NaOH in moles/liter is
0.206 M 5.43 x 103 M 0.115 M 114 M
0.206 M 5.43 x 103 M 0.115 M 114 M 0.206 M 5.43 x 103 M 0.115 M 114 M

Explanation / Answer

First balance theequation HCl (aq) + NaOH (aq) ----> H2O (l) + NaCl (aq) HCl and NaOH react in a 1:1 ratio Given Molarity = M = moles solute / L soln 0.154 M HCl 33.5 mL of HCl soln titrated 25 mL of ? M NaOH soln (0.154 mol HCl / 1 L HCl soln)(1L HCl soln / 1000 mL HClsoln)(33.5 HCl mL soln)(1 molNaOH / 1 mol HCl)( 1 / 25 mL NaOHsoln)(1000 mL NaOH soln/ 1 L NaOH soln) = 0.206M NaOH

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