One reaction involved in the conversion of iron ore to themetal is FeO(s)+CO(g)-

Question

One reaction involved in the conversion of iron ore to themetal is FeO(s)+CO(g)------>Fe(s)+CO2(g) Calculate the standard enthalpy change for this reaction fromthese reactions of iron oxides with CO: 3 Fe2O3(s)+CO(g)-----> 2Fe3O4(s)+CO2(g)  H= -47 kj Fe2O3(s)+ 3CO(g)------>2 Fe(s) + 3CO2(g)    H= -25kj Fe3O4(s)+CO(g)----->3FeO(s)+CO2(g) H= 19kj Show how you did each step and explain to recieve kharmapoints thanks for the help One reaction involved in the conversion of iron ore to themetal is FeO(s)+CO(g)------>Fe(s)+CO2(g) Calculate the standard enthalpy change for this reaction fromthese reactions of iron oxides with CO: 3 Fe2O3(s)+CO(g)-----> 2Fe3O4(s)+CO2(g)  H= -47 kj Fe2O3(s)+ 3CO(g)------>2 Fe(s) + 3CO2(g)    H= -25kj Fe3O4(s)+CO(g)----->3FeO(s)+CO2(g) H= 19kj Show how you did each step and explain to recieve kharmapoints thanks for the help

Explanation / Answer

We need to fined H for FeO(s)+CO(g)------>Fe(s)+CO2(g) FeO(s)+CO(g)------>Fe(s)+CO2(g) (3 Fe2O3(s)+CO(g)-----> 2Fe3O4(s)+CO2(g) ) H= -47 kj   ..........>I 3(Fe2O3(s)+ 3CO(g)------>2Fe(s) + 3 CO2(g) ) H = 3(  H= -25kj ) = -75kJ   ...........>II II -I will give 8CO (g) .............> 6Fe(s) + 8CO2(g) -2 Fe3O4(s) 2 Fe3O4(s) + 8CO (g) ...............>6Fe(s) + 8 CO2(g)    H = -75kJ- (-47kJ) = -28kJ   .............>III Fe3O4(s) + 4CO (g)...............> 3Fe(s) + 4CO2(g)    H = {-75kJ -(-47kJ)}/2 = -14kJ   .............>IV Fe3O4(s)+CO(g)----->3FeO(s)+CO2(g) H= 19kJ ..........>V IV -V will giv e 3CO(g) ..........> 3Fe(s) + 4 CO2(g)- 3 FeO(s) -CO2(g)           H = -14kJ - 19kJ = -33kJ 3CO(g) + 3 FeO(s)..........> 3Fe(s)+ 3CO2(g)   CO(g) + FeO(s)..........> Fe(s)+ CO2(g)       H = -33kJ / 3   = -11kJ (3 Fe2O3(s)+CO(g)-----> 2Fe3O4(s)+CO2(g) ) H= -47 kj   ..........>I 3(Fe2O3(s)+ 3CO(g)------>2Fe(s) + 3 CO2(g) ) H = 3(  H= -25kj ) = -75kJ   ...........>II II -I will give 8CO (g) .............> 6Fe(s) + 8CO2(g) -2 Fe3O4(s) 2 Fe3O4(s) + 8CO (g) ...............>6Fe(s) + 8 CO2(g)    H = -75kJ- (-47kJ) = -28kJ   .............>III Fe3O4(s) + 4CO (g)...............> 3Fe(s) + 4CO2(g)    H = {-75kJ -(-47kJ)}/2 = -14kJ   .............>IV Fe3O4(s)+CO(g)----->3FeO(s)+CO2(g) H= 19kJ ..........>V IV -V will giv e 3CO(g) ..........> 3Fe(s) + 4 CO2(g)- 3 FeO(s) -CO2(g)           H = -14kJ - 19kJ = -33kJ 3CO(g) + 3 FeO(s)..........> 3Fe(s)+ 3CO2(g)   CO(g) + FeO(s)..........> Fe(s)+ CO2(g)       H = -33kJ / 3   = -11kJ

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