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1) The following reaction is given: 2NiS 2 +5O 2 (arrow) 2NiO + 4SO 2 When 11.2g

ID: 687414 • Letter: 1

Question

1) The following reaction is given: 2NiS2 +5O2 (arrow) 2NiO + 4SO2     When 11.2g of NiS2 reactwith 5.43g of O2, 4.86g of NiO are obtained.    a) Determine the limiting reactant, theoritcalyield of NiO, and % yield for the reaction.     b) How much of the excess reactant isremaining?                    1) The following reaction is given: 2NiS2 +5O2 (arrow) 2NiO + 4SO2     When 11.2g of NiS2 reactwith 5.43g of O2, 4.86g of NiO are obtained.    a) Determine the limiting reactant, theoritcalyield of NiO, and % yield for the reaction.     b) How much of the excess reactant isremaining?     When 11.2g of NiS2 reactwith 5.43g of O2, 4.86g of NiO are obtained.    a) Determine the limiting reactant, theoritcalyield of NiO, and % yield for the reaction.     b) How much of the excess reactant isremaining?                   

Explanation / Answer

a)   The given reaction is     2NiS2 +5O2  ------>    2NiO +4SO2    moles of NiS2 =grams of NiS2 / (gram/mol ) NiS2                          = 11.2g /122.7 g/mol                          = 0.09 mol moles ofOxygen is = grams of O2 / (gram/mol )O2                              =  5.43g/ 31.9989 g/mol                             =0.16969 mol 2moles of NiS2 is reacted with 5 molesof O2 0.09 moles   ----------- ? molesof Oxygen                         From crass multiplication method                        = 0.09*5 / 2                      = 0.225 moles of Oxygen is required .      But Here only 0.16969 moles arepresent .     So the limiting reagent isOxygen.   Thereotical yield of NiO is     5 moles of Oxygen is consumed for 2moles of NiO      0.16969 moles -----------? molesof NiO      From cross multiplicationmethod =0.16969*2/5=0.067876 moles      weight of the NiO is =0.067876 moles* 165.39 g/mol                                 = 11.22601164 g               % of yield = (4.86g/11.22601164 g)*100                                 =43.29 % b) Excess reactant      5 moles of Oxygen is is consumed for2 moles of NiS2           0.16969moles of Oxygen is consumed for -----? moles ofNiS2                         0.16969*2 /5 =0.067876 moles        Excess reagent is =(0.09  -0.067876 ) moles                                   =0.022124 moles                                   = 0.022124 moles *122.7 g/mol                                   = 2.71461 g of NiS2           0.16969moles of Oxygen is consumed for -----? moles ofNiS2                         0.16969*2 /5 =0.067876 moles        Excess reagent is =(0.09  -0.067876 ) moles                                   =0.022124 moles                                   = 0.022124 moles *122.7 g/mol                                   = 2.71461 g of NiS2