If the enthalpy of combustion for glucose is -2802 kJ/mol, howmany kJ of heat ar

Question

If the enthalpy of combustion for glucose is -2802 kJ/mol, howmany kJ of heat are produced per gram of water produced? (The answer is -25.92 kJ/mol, but I dont know how to do it.Please show your work.) If the enthalpy of combustion for glucose is -2802 kJ/mol, howmany kJ of heat are produced per gram of water produced? (The answer is -25.92 kJ/mol, but I dont know how to do it.Please show your work.)

Explanation / Answer

C6H12O6 +6O2------------------->6CO2 +6H2O..........H= -2802 kJ/mol 6 x 18 =108 g water is produced. For 108 g water H= -2802 kJ For 1g water H= -2802/108= -25.94 kJ...(Ans)

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