calculate pH after adding 0.010 M HCl to 1000 mL of a buffer solution. containin

Question

calculate pH after adding 0.010 M HCl to 1000 mL of a buffer solution. containing 0.10M acetic acid ( HC2H3O2) and 0.10M sodium acetate (Na C2H3O2).   Ka=1.8 x10^-5

Explanation / Answer

Here volume of the HCl acid is not mentioned. So i amconsidering it as "x"L. Number of moles of acetic acid = 0.10 M * 1L                                                  = 0.10 moles Number of moles of sodium acetate = 0.10 M * 1.0 L                                                      = 0.10 moles                                              pKa = 4.7447                                                                      CH3COO- (aq)   + H+ (aq)  ---------------->    CH3COOH (aq) Beforerxn                                                            0.10moles                                                           0.10                                                                                                     x * 0.010 Afterrxn                                                              0.10 - x*0.010          0       0.10 + x * 0.010                     pH = 4.7447 + log ( 0.10 - x * 0.010 / 0.10 + x* 0.010 ) Once we know the volume of the acid, we can solve the problem forpH. Hope this will surely help you.

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