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I\'m having extreme difficulty with my pre-lab write-up. I\'m notsure whether it

ID: 688408 • Letter: I

Question

I'm having extreme difficulty with my pre-lab write-up. I'm notsure whether it's because the questions are challenging, or becausethe prof hasn't covered the material in lecture yet... But any helpat all would be appreciated.

1. Why is vapour pressure of water and important experimentaldetail in calculating the molar volume of nitrogen?

2. If we were to react 0.146g of Sulfamic Acid with 0.120g ofSodium Nitrite, what volume (ml) of gas would we expect to beproduced at standard temperature and pressure?

Explanation / Answer

We Know that :       In order to calculate the molarvolume of Nitrogen gas we should have to take care with respect tothe vapour pressure of water vapor As the Nitrogen gas is collected on thewater so the N2 gas is aquated which acts as impurity in orderto calculate the molar volume of N2 we have to subtractthe pressure due to aqueous tension from Total pressure whichgives pressure due to dry N2 gas from where the calculationgives the correct molar volume occupied by the gas.          The Reactionof Sulfamic acid with Sodium Nitrite gives the followingproducts as :         NaNO2(aq) +HSO3NH2(s)-------------> NaHSO4(aq) + H2O(l) + N2(g)         number of molesof NaNO2 = 0.120 g / 68.99 g / mol                                                      = 0.00173 mol         number of moles ofHSO3NH2 = 0.146 g / 97.09 g / mol                                                           = 0.0015 mol         Hence the number ofmoles of Sulfamic acid acts as limiting reagent hence the number ofmoles of N2 gas liberated         0.0015 mol          The volumeoccupied by the N2 gas at the S.T.P condition is 0.0015 mole x 22.4L / mole                                                                                                     = 0.0336 L                                                                                                       = 33.6 mL         
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