The question is: consider the double replacement, metathesisreaction: Potassium
ID: 688548 • Letter: T
Question
The question is: consider the double replacement, metathesisreaction:Potassium Phosphate+ Magnesium sulfate (arrow)
(a) write the net ionic reaction.
I know that the ions will shift partners but I cant get the chargesbalanced right.
(b)If 100.0 mL of a 0.42 solution of Magnesium Sulfate are requiredto compeletly react with 77.2mL of Potassium Phosphate, What is theMolarity of the Potassium Phosphate Solution.
This seems like a limiting reagent problem so would I find theamount of moles then put mol/L?
Explanation / Answer
a)
2K3PO4 + 3MgSO4 = 3K2SO4 + Mg3(PO4)2
PO4 is insoluble, except with compounds of NH4+ and the alkalimetal cations (Group 1A)
Mg is not in Group 1A, so Mg3(PO4)2 is insoluble.
The ionic equation is:
6K + 2PO4 +3Mg + 3SO4 = 6K + 3SO4 + Mg3(PO4)2
Now, remove the ones that appear on both sides.
Cancel 6K, and 3SO4 from both sides
This leaves, 2PO4 +3Mg = Mg3(PO4)2
That is your net ionic equation. You shoud also show the ioncharges Mg is 2- and PO4 is 3+
b)
You want to use the equation:
Molarity1 X Volume 1 = Molarity2 X Volume2
(.42M)(.1L) = (M2)(.1 + .0772)
The Molarity of the Potassium Phosphate is.237M.
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