You have a 5.82 calorimeter containing some water at roomtemperature (22.0degC).

Question

You have a 5.82 calorimeter containing some water at roomtemperature (22.0degC). When you add 40.33g boiling water, thetemperature raises to 50.9degC. The calorimeter constant is160.8J/degC. Atmospheric pressure is 760mmhg. The specific heat ofwater is 4.184J/gdegC. Show all work,include all unites. Make suresigns are correct. 1.Calculate the heat flow for the hot water. 1b. Calculate the heat flow of the cold water. 1c. Calculate how much cold water was added. You have a 5.82 calorimeter containing some water at roomtemperature (22.0degC). When you add 40.33g boiling water, thetemperature raises to 50.9degC. The calorimeter constant is160.8J/degC. Atmospheric pressure is 760mmhg. The specific heat ofwater is 4.184J/gdegC. Show all work,include all unites. Make suresigns are correct. 1.Calculate the heat flow for the hot water. 1b. Calculate the heat flow of the cold water. 1c. Calculate how much cold water was added.

Explanation / Answer

Mass of boiling water =40.33 g Heat flow for hot water = (mass * specific heat * temperaturedifference) + (mass * heat of vaporization)                                     =(40.33 g * 4.18 J/ (g.C) * (100 - 50.9)) + (40.33 g * 2257J/g)                                     =99302 J                                     =99.3 kJ . Heat flow for the cold water = Mass *s pecific heat *temperature difference                                           = mass * 4.18 J/(g.C) * (50.9 - 22)C . Heat given by hot water is absorbed by cold water andcalorimeter 99302 J = mass * 4.18 J/(g.C) * (50.9 - 22)C  + 160.8 J/C * (50.9 - 22) C Mass = 783.5 g This is the mass of cold water added.

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