Sodium Phosphate reacts with magnesium chloride according tothe following equati

Question

Sodium Phosphate reacts with magnesium chloride according tothe following equation. If you need 4.5 mole of magnesium phosphatehow many moles of each reactant do you need for eachreaction? 2Na3PO4 + 3MgCl2 = Mg3(PO4)2 + NaCl Please break it into each step mathmatically.....im so lostwith this question..... Sodium Phosphate reacts with magnesium chloride according tothe following equation. If you need 4.5 mole of magnesium phosphatehow many moles of each reactant do you need for eachreaction? 2Na3PO4 + 3MgCl2 = Mg3(PO4)2 + NaCl Please break it into each step mathmatically.....im so lostwith this question.....

Explanation / Answer

1.) 4.5 mol Mg3(PO4)2 ( 2 mol Na3PO4/ 1 mol Mg3(PO4)2)= 9 moles of Na3PO4 needed The simple math looks like 4.5(2/1) = 9 When looking at the equation given, the coefficients representthe number of moles of each molecule. So, from the equation youknow that there are 2 moles of Na3PO4, 3 moles of MgCl2, 1 mol ofMg3(PO4)2, and 1 mol of NaCl. The question tells you that you have4.5 mol of magnesium phosphate aka Mg3(PO4)2. All you have to do isset up simple ratios using the 4.5 mol Mg3(PO4)2 and the molesgiven in the equation. You want to cancel out moles of Mg3(PO4)2 inorder to solve for the theoretical amounts of the reactants. 2.) 4.5 mol Mg3(PO4)2 (3 mol MgCl2/ 1 mol Mg3(PO4)2) = 13.5mol of MgCl2 needed The simple math looks like this : 4.5(3/1) = 13.5 I hope this helps. If you still dont understand just let meknow and I will try to explain further.

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