I need to determine the concentration of my standard solutionsfor a spectrophoto

Question

I need to determine the concentration of my standard solutionsfor a spectrophotometric lab: The concentration of my stock iron solution is 9.86 ppm. I made five standard solutions using 1.00 mL, 2.00 mL, 5.00mL, 10.00 mL, and 25.00 mL of the stock solution. Eachstandard solution was brought to a volume of 100.00 mL. How do I find the concentrations of each standard solution inppm? Because ppm = g/mL, do I multiply 9.86 ppm by the mL ofstock solution used, then divide by the total mL ofsolution? Any help/insight is greatly appreciated! I need to determine the concentration of my standard solutionsfor a spectrophotometric lab: The concentration of my stock iron solution is 9.86 ppm. I made five standard solutions using 1.00 mL, 2.00 mL, 5.00mL, 10.00 mL, and 25.00 mL of the stock solution. Eachstandard solution was brought to a volume of 100.00 mL. How do I find the concentrations of each standard solution inppm? Because ppm = g/mL, do I multiply 9.86 ppm by the mL ofstock solution used, then divide by the total mL ofsolution? Any help/insight is greatly appreciated!

Explanation / Answer

Here we have to follow the dilution law. MV = M'V' M = Concentration of stock solution = 9.86 ppm V = Volume of stock solution = 1 mL M' = concentration of solution prepared = ? V = Volume of the diluted solution prepared = 100 mL Plug the values we get M' = MV /V'                                        = 0.0986 ppm Simillarly do the same for all thesolutions i.e., multiply 9.86 with Volume of stock solution &divided by 100

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