In a lab, a student uses a \"coffee cup\" calorimeter todetermine the specific h

Question

In a lab, a student uses a "coffee cup" calorimeter todetermine the specific heat of a metal. She heats 19.4 grams ofChromium of 97.85oC and then drops it into a cupcontaining 82.6 grams of water at 20.96oC. She measuresthe final temp to be 22.92oC. Assuming that all of theheat is transferred to the water, she calculates the specific heatof chromium to be _______ J/goC. In a lab, a student uses a "coffee cup" calorimeter todetermine the specific heat of a metal. She heats 19.4 grams ofChromium of 97.85oC and then drops it into a cupcontaining 82.6 grams of water at 20.96oC. She measuresthe final temp to be 22.92oC. Assuming that all of theheat is transferred to the water, she calculates the specific heatof chromium to be _______ J/goC.

Explanation / Answer

so for this problem, you need the equation for heat in acalorimeter: (Mass H2O)(Specific heat H2O)(T) = (Mass of Metal)( Specificheat of metal)(T) Now we have to decide what is gaining heat and what is losing heat.The water is gaining the heat and the metal is losing heat so theequation should look like this: (Mass H2O)(Specific heat H2O)(T) = - (Mass of Metal)(Specific heat of metal)(T) The specific heat for water is 4.16, so now plug in the values: (82.6g H2O)(4.16)(22.92-20.96) = - (19.4 gmetal)(C)(22.92-97.85) rearrange for C: 673.48 = - (-1453.6C) 673.48 = 1453.6C C = 0.4633 Hope this helped. Don't forget to give Karma please.

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