When Al is obtained by electroysis fromAl 2 O 3 , the minimum number of coulombs

Question

When Al is obtained by electroysis fromAl2O3, the minimum number of coulombsrequired to produce 1.00 mole of aluminum isapproximately:
A.   32,200 B.   64,200 C.   96,500 D.   193,000 E.   290,000 When Al is obtained by electroysis fromAl2O3, the minimum number of coulombsrequired to produce 1.00 mole of aluminum isapproximately:
A.   32,200 B.   64,200 C.   96,500 D.   193,000 E.   290,000

Explanation / Answer

When Al is obtained by electroysis fromAl2O3, the minimum number of coulombsrequired to produce 1.00 mole of aluminum is approximately: here oxidation number of alumium in Al2O3 is --> 2x - 6 = 0                                                                               x = + 3 so 3 moles of electrons is required i.e charge = 3F where F is faraday and 1 faraday = 96500 coulomb so total charge = 3*96500 coulomb                       = 289500 coulomb so answer is nearest to last option and so answer is 290000coulomb

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