Calculate the H for Ca(s) + 1/2O 2 (g) +CO 2 (g) => CaCO 3 (s) given the informa

Question

Calculate the H for Ca(s) + 1/2O2(g) +CO2(g) => CaCO3(s)
given the information below.
Ca(s) + 1/2O2(g) => CaO(s) H = -650 kJ
CaCO3(s) => CaO(s) + CO2(g) H = +200kJ
C(s) + O2(g) => CO2(g) H = -394 kJ

Explanation / Answer

we need to find enthalpy change for the reaction: H for Ca(s) + 1/2O2(g) + CO2(g) =>CaCO3(s) so here we see three reactions: Ca(s) + 1/2O2(g) => CaO(s) H = -650kJ          -----------(1) CaCO3(s) => CaO(s) + CO2(g) H = +200kJ     -------------(2) C(s) + O2(g) => CO2(g) H = -394kJ               -------------(3) now we take eq 1 - eq2 we get: Ca(s) + 1/2O2(g) -CaCO3(s) => CaO(s) -CaO(s) - CO2(g) we get our desired reaction as: Ca(s) + 1/2O2(g) + CO2(g) =>CaCO3(s) so enthaply change is = H1 - H2                                  = -650 - 200 KJ                                 = -850 KJ

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