and can you tell me why it is either diamagnetic or paramagneticplease (a) RuO 1
ID: 689878 • Letter: A
Question
and can you tell me why it is either diamagnetic or paramagneticplease(a) RuO 1 diamagnetic paramagnetic
(b) CuCl 2 diamagnetic paramagnetic
(c) NiCl2 3 diamagnetic paramagnetic
(d) Mo2O3 4 diamagnetic paramagnetic
(e) NbCl5 5 diamagnetic paramagnetic 1 diamagnetic paramagnetic 1 diamagnetic paramagnetic 1 2 diamagnetic paramagnetic 2 diamagnetic paramagnetic 2 3 diamagnetic paramagnetic 3 diamagnetic paramagnetic 3 4 diamagnetic paramagnetic 4 diamagnetic paramagnetic 4 5
Explanation / Answer
a) The given compoundis RuO Here Ru oxidation stateis +2 state (Ru2+ ) The Electroniccofiguration of Ru2+ is4d65s0 Here the number ofUnpaired electrons is 4. 'n' is the number of unpairedelectrons. Magnetic moment,=n*(n+2)=4*6 = 4.89BM Since the magnetic moment is not equal tozero, it is paramagnetic. Since the magnetic moment is not equal tozero, it is paramagnetic. SoRuO is having paramagnetic nature . b) The given compound is CuCl Here Cu oxidation state is+1 state (Cu+) The stable Electroniccofiguration of (Cu+) is3d104s0 Here the number ofUnpaired electrons is 0 So=0.0 BM Since magnetic moment is equal to zero, itis diamagnetic. Since magnetic moment is equal to zero, itis diamagnetic. So CuClis having diamagnetic nature . c) The given compound is NiCl2 Here Nioxidation state is +2 state (Ni2+ ) The Electronic cofiguration ofNi2+is 3d84s0 Here the number ofUnpaired electrons is 2 =n*(n+2)=2*4 =2.82 BM SoNiCl2 is having paramagnetic nature . d) The given compound is Mo2O3 Herethe oxidation state of Mo is +3 Theelectronic configuration of Mo3+ is4d35s0 Here thenumber of Unpaired electrons is 3 =n*(n+2)=3*5 =3.87BM SoMo2O3 is havingparamagnetic nature . e) The given compoundis NbCl5 Herethe oxidation state of Nb is +5 The electronicconfiguration of Nb+5 is4d05s0 Here thenumber of Unpaired electrons is 0 So =0.0 BM So NbCl5 is having diamagneticnature Here thenumber of Unpaired electrons is 3 =n*(n+2)=3*5 =3.87BM SoMo2O3 is havingparamagnetic nature . e) The given compoundis NbCl5 Herethe oxidation state of Nb is +5 The electronicconfiguration of Nb+5 is4d05s0 Here thenumber of Unpaired electrons is 0 So =0.0 BM So NbCl5 is having diamagneticnature Herethe oxidation state of Nb is +5 The electronicconfiguration of Nb+5 is4d05s0 Here thenumber of Unpaired electrons is 0 So =0.0 BM So NbCl5 is having diamagneticnature So =0.0 BM So NbCl5 is having diamagneticnatureRelated Questions
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