consider the reaction: 2HCL(aq) + Ba(OH) 2 (aq) ---->BaCl 2 (aq) + 2H 2 O(l) H=

Question

consider the reaction: 2HCL(aq) + Ba(OH)2(aq) ---->BaCl2(aq) + 2H2O(l) H= -118 Calculate the heat when 100 mL of 0.5 M HCl is mixed with300mL of 0.1M Ba(OH)2. Assuming that the temperature ofboth solutions was initially 25 C and that the final mixture has amass of 400.0 g and a specific heat capacity of 4.18 J/C.gcalculate the final temperature of the mixture. consider the reaction: 2HCL(aq) + Ba(OH)2(aq) ---->BaCl2(aq) + 2H2O(l) H= -118 Calculate the heat when 100 mL of 0.5 M HCl is mixed with300mL of 0.1M Ba(OH)2. Assuming that the temperature ofboth solutions was initially 25 C and that the final mixture has amass of 400.0 g and a specific heat capacity of 4.18 J/C.gcalculate the final temperature of the mixture.

Explanation / Answer

First, find out if there is a limiting reactant in this problem.See how many moles of each reactant are being combined. Molarity = moles / liter HCl: .5=x/.1 .05 moles HCl Ba(OH)2: .1=x/.3 .03 moles Ba(OH)2 If you look at the reaction, you need twice the number of moles ofHCl as Ba(OH)2. We don't have that, so HCl is the limitingreactant. For every 2 moles of HCl reacted, -118 kJ are released. .05 mol HCl * -118 kJ/2 mol HCl H=-2.95 kJ Use the equation q=mcT to find the temperature change. 2950 J = 400.0 g * 4.18 J/Cg * T 1.764354067 = T Final temp: 26.76435407 C (don't forget to round for significantfigures)

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