1) There are two compounds of titanium and chlorine. Onecompound contains 31.04%

Question

1) There are two compounds of titanium and chlorine. Onecompound contains 31.04% titanium by mass, and the second contains74.76% chlorine by mass. (a) What are the ratios of titanium to chlorine atoms inthe first compound? (b) What are the ratios of titanium to chlorine in thesecond compound? 1) There are two compounds of titanium and chlorine. Onecompound contains 31.04% titanium by mass, and the second contains74.76% chlorine by mass. (a) What are the ratios of titanium to chlorine atoms inthe first compound? (b) What are the ratios of titanium to chlorine in thesecond compound?

Explanation / Answer

In the first compound the % of Chlorine = 100 - % oftitanium                                                             = 100 - 31.04                                                             = 68.96 % In the first compound the % of Titanium = 100 - %of Chlorine                                                              = 100 - 74.76                                                             = 25.24 % No . of moles of Titanium in 1st compound , N = mass / atomicmass                                                                       =31.04 /47.88              atomic mass of Ti = 47.88 g                                                                       = 0.6482 mol 1 mole of Ti contains 6.023 * 10^23 atoms 0.6482 mole of Ti contains Xatoms X = ( 0.6482 * 6.023 * 10^23 ) = 3.904 * 10^23 atoms No . of moles of Chlorine in 1st compound , N =mass / atomic mass                                                                       =68.96/ 35.5                                                                                    = 1.9425 mol 1 mole of Cl contains 6.023 * 10^23 atoms 1.9425 mole of Cl contains Yatoms Y = ( 1.9425 * 6.023 * 10^23 ) = 11.699 * 10^23atoms ratios of titanium to chlorine atoms in the first compound = 3.904 * 10^23 / 11.699*10^23                                                                                      = 0.333                                                                                     = 1:3 Simillarly do the second one                                             In the first compound the % of Titanium = 100 - %of Chlorine                                                              = 100 - 74.76                                                             = 25.24 % No . of moles of Titanium in 1st compound , N = mass / atomicmass                                                                       =31.04 /47.88              atomic mass of Ti = 47.88 g                                                                       = 0.6482 mol 1 mole of Ti contains 6.023 * 10^23 atoms 0.6482 mole of Ti contains Xatoms X = ( 0.6482 * 6.023 * 10^23 ) = 3.904 * 10^23 atoms No . of moles of Chlorine in 1st compound , N =mass / atomic mass                                                                       =68.96/ 35.5                                                                                    = 1.9425 mol 1 mole of Cl contains 6.023 * 10^23 atoms 1.9425 mole of Cl contains Yatoms Y = ( 1.9425 * 6.023 * 10^23 ) = 11.699 * 10^23atoms No . of moles of Chlorine in 1st compound , N =mass / atomic mass                                                                       =68.96/ 35.5                                                                                    = 1.9425 mol 1 mole of Cl contains 6.023 * 10^23 atoms 1.9425 mole of Cl contains Yatoms Y = ( 1.9425 * 6.023 * 10^23 ) = 11.699 * 10^23atoms 1 mole of Cl contains 6.023 * 10^23 atoms 1.9425 mole of Cl contains Yatoms Y = ( 1.9425 * 6.023 * 10^23 ) = 11.699 * 10^23atoms ratios of titanium to chlorine atoms in the first compound = 3.904 * 10^23 / 11.699*10^23                                                                                      = 0.333                                                                                     = 1:3 Simillarly do the second one                                            

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