Hello all! This is a seemingly simple balancing redox reactionproblem, but every

Question

Hello all! This is a seemingly simple balancing redox reactionproblem, but everytime I input into the computer homework itswrong. Please help! If you could show step by step how you obtainedit, it would be greatly appreciated! Write a balanced equation for the following by using theappropriate stoichiometric quantities of H+ in the reactnats andh2o in products: CH3CH2OH + Cr207(2-) ----> CO2 + Cr(3+) (The numbers in parrentheses indicate charge.) Hello all! This is a seemingly simple balancing redox reactionproblem, but everytime I input into the computer homework itswrong. Please help! If you could show step by step how you obtainedit, it would be greatly appreciated! Write a balanced equation for the following by using theappropriate stoichiometric quantities of H+ in the reactnats andh2o in products: CH3CH2OH + Cr207(2-) ----> CO2 + Cr(3+) (The numbers in parrentheses indicate charge.)

Explanation / Answer

    Oxidation half reaction:         CH3CH2OH --------> 2 CO2 + 9e           In order to balance the number of oxygen atoms add 3 moles of wateron the reactant side and 6moles of H+           on the product side.          CH3CH2OH + 3 H2O ---------> 2 CO2 + 9e + 6H+          Reductionhalf reaction :
       14H++ Cr2O7-2 + 6e-------> 2 Cr+3 + 7H2O           Inorder to balance the above reaction multiply the equation 1by 6 and equation 2 by 9 we get               18 H2O + 6 CH3CH2OH --------> 12 CO2 + 36 H+ + 54 e                 126 H+ + 9Cr2O7-2 + 54 e --------> 18 Cr+3 + 63 H2O           Addingthe above set of equations we get :              6 CH3CH2OH   + 9Cr2O7-2 + 90H+ ---------> 12 CO2 +18 Cr+3 + 45 H2O          Reductionhalf reaction :
       14H++ Cr2O7-2 + 6e-------> 2 Cr+3 + 7H2O           Inorder to balance the above reaction multiply the equation 1by 6 and equation 2 by 9 we get               18 H2O + 6 CH3CH2OH --------> 12 CO2 + 36 H+ + 54 e                 126 H+ + 9Cr2O7-2 + 54 e --------> 18 Cr+3 + 63 H2O           Addingthe above set of equations we get :              6 CH3CH2OH   + 9Cr2O7-2 + 90H+ ---------> 12 CO2 +18 Cr+3 + 45 H2O

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