At elevated temperature, NO2 reacts with CO to produce CO2 andNO. Two possible m

Question

At elevated temperature, NO2 reacts with CO to produce CO2 andNO.

Two possible mechanisms are suggested :

A

CO + NO2 CO2 + NO


B

2NO2 NO3 + NO (slow)

NO3 + CO NO2 + CO2 (fast)

Which of the following are true statements ?

a) The rate law for mechanism A is k[CO][NO2].

b) Only mechanism A gives the correct overall reaction.

c) In mechanism B carbon monoxide will not appear in the rate lawbecause it participates in the mcheanism after therate-determining step.

d) The rate law for mechanism B is k[NO2].

Explanation / Answer

    The given reaction is     CO + NO2 CO2 + NO     The mechanism for this reaction is      2NO2 NO3 + NO (slow)
     NO3 + CO NO2 + CO2 (fast) 1)Rate law for the mechanism A is       Rate = rate constant*the product of [reactants ]                = k[CO][NO2].        So the statement A iscotrrect answer 2) Only mechanism A gives the correct overallreaction.This is wrong .Because the overall reaction is depends onRate determining step.     The slowest step in the over allreaction mechanism is the rate determining step.     In the rate determining step Rate = k[NO2]2     So the statement B is wrong 3) In mechanism B carbon monoxide will not appear in therate law because it participates in the mcheanism after therate-determining step.    The rate law only applicable for rate determiningsteo .    So in the rate determing step CO didn'tparticipating .So thestatement is also correct 4) The rate law for mechanism B is k[NO2]    The rate law for the MEchanism B isk[NO2]2    So this statement is wrong    So this statement is wrong

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.