The reaction of 1-hexene with HBr yields two isomeric products: 1-bromohexane an
ID: 691996 • Letter: T
Question
The reaction of 1-hexene with HBr yields two isomeric products: 1-bromohexane and 2-bromohexane. You set up an experiment to carry out this reaction, using 4.0 mL of 30% hydrogen bromide in propanoic acid (density 1.31 g/mL), followed by 1.50 mL of 1-hexene (density 0.67 g/mL). After distilling your reaction mixture, you collect 0.712 grams of product.
A. How many grams of 1-Hexene and HBr were used in this reaction? How many moles?
B. What is the theoretical yield of product?
C. What is the percent yield?
Explanation / Answer
a)
mass of 1hexene = D*V = 0.67*1.5 = 1.005 g of 1hexene
mass of HBr = D*V*% = 4*0.30*1.31 = 1.572 g of HBr
b)
mol of 1hexne = mass/MW = 1.005 /84.1595= 0.01194
mol of HBr = mass/MW = 1.572 /80.9119 = 0.01942
ratio is 1:1 so
hexene is limiting
expect --> 0.01194 mol of haloalkane
MW of 1-bromohexnae = 165.071
mass = mol*MW = 0.01194*165.071 = 1.97094
c)
%yield = real/theoretical*100% = 0.712/1.97094*100 = 36.124 %
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