1 po H2 and N2 react to form NH3 by the equation 3H2(g) + N2(g) 2NH3(g) if a rea
ID: 692034 • Letter: 1
Question
1 po H2 and N2 react to form NH3 by the equation 3H2(g) + N2(g) 2NH3(g) if a reaction vessel initial contained 300 H2 molecules and 150 N2 molecules, which molecules would be present i the reaction proceeds completely towards productra o a. 150 H2 molecules; No N2 molecules; 150 NH3 molecules b. No H2 molecules; 50 N2 molecules; 200 NH3 molecules c. No H2 molecules; 50 N2 molecules; 100 NH3 molecules d. No H2 molecules; No N2 molecules; 200 NH3 molecules Moving to the next question prevents changes to this answerExplanation / Answer
From the given reaction we see that 3 molecules of H2 reacts with one molecule of N2 to produce 2 molecules of NH3.
If 300 H2 molecules react than 300/3 = 100 molecules of N2 are consumed and 200 molecules of NH3 should be produced. However, the reaction vessel initially had 150 molecules of N2, thus 50 molecules of N2 remain in the vessel if the reaction proceeds completely towards the product.
Hence, the correct answer is B
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