2NH 3 (g)-N2(g) + 3H 2 (g) Go = 34H Now suppose a reaction vessel is filled with

Question

2NH 3 (g)-N2(g) + 3H 2 (g) Go = 34H Now suppose a reaction vessel is filled with 0.127 atm of ammonia (NH,) and 0.120 atm of hydrogen (H2) at 500. °C. Answer the ollowing questions about this system: o rise fall To Under these conditions, will the pressure of H 2 tend to rise or fall s it possible to reverse this tendency by adding N2 Inother words, ar you said the pressure of H 2 will tend to nse, can that be changed to a tendency to falil by adding N27 Similarly, if you said the pressure of H2 will tend to fall, can that be changed to a tendency to rae by adding N2 If you said the tendency can be reversed in the second question, calculate o yes minimum pressure of N 2 needed to reverse it Round your answer to 2 significant digits

Explanation / Answer

as there is no N2 in the bigening, forward reaction takes place.

so that, pressure of H2 will rise.

yes, it is possible.

DG0 = -RTlnK

34*10^3 = -8.314*773.15lnK

K = 5.04*10^-3

K = pH2^3*pN2/pNH3^2

5.04*10^-3 = (0.12+3x)^3*x/(0.127-2x)^2

x = 0.013

partial pressure of N2 = 0.013 atm

minimum pressure of N2 required to reverse = 0.013 atm

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