If the (Zn21 -2.0 M and (Ai Using the equation to ard cell. and [A)- 0.50 M, thi

Question

If the (Zn21 -2.0 M and (Ai Using the equation to ard cell. and [A)- 0.50 M, this would be a noh an we can come up w AG- calculate nonsnd 4G - -nF non-standard cell potentials, the Nernst equation. where n = # moles of electrons in the balanced half-reactions -faradays constant a 96,000 C/rnol Q = reaction quotient. [products' , [reactants) 4. Calculate IZn2] 2.0 M and [AP'1 -0.50 M Calculate G and G° and discuss the difference in the work being done. in terms of [products] and [reactants). 5. 6. What is the effect on of doubling the size of the aluminum electrode? 7. What is the effect on of adding 500 mL of water to the cathode, assuming there was 1 L of the solution to begin with?

Explanation / Answer

the reaction:

Al3+(aq) + 3e– Al(s) –1.66

Zn2+(aq) + 2e– Zn(s) –0.76

Balance

3Zn2+ + 2Al(s) -- > 2Al3+ + 3Zn(s)

c)

therefore, there are 3x2 = 6 electrons of moles being transferred

b)

E º = Ered - Eox = -0.76 -- 1.66 = 0.9 V

now

Q = [Al3+]^2 / [Zn+2 ]^3

a)

Q = (0.5^2)/ (2^3) = 0.03125

d)

E = E º - 0.0592/(n) log(Q)

E = 0.90 - 0.0592/(6) * log(0.03125) = 0.91485 V

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