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View History Bookmarks C ) Secure : ps://www-awh.aleks.com/alekscgi/x/Isl.exe/1o u-lg CHEM215 F17-02 | 1 of 2 When a lead acid car batery is echarged by the alternator, i acts essentally as an electrolytic cell in which solid leadlth slfate (Pbso4) is reduced to lead at the cathode and oxidized to solid leadI) oxide (PbO) at the anode. Suppose a current of 39.0 A is fed into a car battery for 55.0 seconds Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol. . Calculatethe mass of lead deposited on the cathode of the battery. [

Explanation / Answer

Faraday's first law of electrolysis state that the amount of substance liberated at the electrode is directly proportional to the quantity of electricity passed through it.

W = ZIt and It = Q

where W is the amount of substance deposited

Z is the electro chemical equivalent

I is the current passed

t is the time

here, I=39 Ampere

t =55 seconds

So Q = 39x 55 =2145 C/s

W = ZQ

Z= E/ 96500

E or equivalent weight of PbSO4 = 151.63

then Z=151.63/96500 = 0.0015

Therefore, W = 0.0015 x 2145 =3.432 g

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