0 Question (2points Buoyancy for the Goodyear blimp Spirit of Innovation comes f
ID: 692416 • Letter: 0
Question
0 Question (2points Buoyancy for the Goodyear blimp Spirit of Innovation comes from 2.03 x 105 ft3 of helium. 1st attempt Part 1 (1 pt) dhi See Periodic Table Calculate the mass of this much helium at 21.00 °C and 0.997 atm pressure. g He Part 2 (1 pt) See Hint Calculate the buoyancy of the balloon as "grams lift"-that is, the difference between the mass of an equal volume of dry air at the same temperature and pressure and the mass of the He in the balloon. Assume the the molar mass of air is 28.8 g/mol. g lift 2020Explanation / Answer
Part 1
Answer
mass of He = 960663g
Explanation
Volume of Helium = 2.05×105ft3
1foot = 3.048dm
Volume in dm3= 2.05×105 × (3.048)3dm3= 5.81×106L
Temperature = 21? = 294.15K
Pressure = 0.997atm
from ideal gas law
no of mole , n = PV/RT
= 0.997atm× 5.81×106L/0.082057(L atm/mol K)× 294.15K
= 239986mol
molar mass of He = 4.003g/mol
Mass of He = 4.003g/mol × 239986mol = 960663g
Part2
Answer
5950934 g lift
Explanation
For equal volume and at same temperature and pressure ,no of mol will not change, so
No of mole of air = 239986mol
molar mass of air = 28.8g/mol
mass of air = 239986mol × 28.8g/mol = 6911597g
Difference in mass = 6911597g - 960663g = 5950934g
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