2) Gas Laws: Steam is heated at a constant pressure (1 bar) from an initial temp
ID: 692428 • Letter: 2
Question
2) Gas Laws: Steam is heated at a constant pressure (1 bar) from an initial temperature of 150 to 250 Using the thermodynamic data provided below, calculate H for: | 250 V,(cm/8)1936.6 2406.1 U, (kJ/kg)2582.7 2733.9 H (ki/kg) 2776.3 22974.5 S (kJ/kg K) 7.61378.0342 150 °C The constants A, B, C, and D for the equation Ca/R A+ BT+CT+DT (T K) are: As 3.470, B-1.45x10-3, c-0, D 0.12 1x105 a. an Ideal Gas b. 0.5507 Pa m6 mol-2 and b-3.04x10-5 a van der Waals gas where a m3 mol1 3) Write the three Laws of Thermodynamics:Explanation / Answer
2.
a.
Cp/R = A + BT + CT2 + DT-2
dH = Cp/R*R*dT
dH = [A + BT + CT2 + DT-2]*R*dT
On integration
H = [AT + BT2/2 + CT3/3 - D/T]*R
Putting upper limit T2 = 250 + 273 = 523 K and lower limit T1 = 423 K
a = 3.47, b = 1.43 *10-3, c = 0, d = 0.121*105
H = [3.47*(523-423) + 1.43*10-3*(5232- 4232)/2 - 0.121*105* (1/523 - 1/423)]*8.314
H = [347 + 67.64 + 5.46]*8.314
H = 3492.7 kJ/kg
3) Three laws of thermodyanmics:
a. First law: Law of conservation of Energy, states that energy cannot be created or destroyed in an isolated system.
b. Second law: Entropy of any isolated system always increases.
c. Third law: The entropy of a perfect crystal at absolute zero temperature is exactly equal to zero.
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