Assign an oxidation state to each element in each reaction and use the change in

Question

Assign an oxidation state to each element in each reaction and use the change in oxidation state to determine which element is being oxidized and which element is being reduced.

1.SbCl5(g)SbCl3(g)+Cl2(g)

Express your answers as signed integers. Enter the initial and the final oxidation states separated by a comma.

Sb:

Cl:

2.CO(g)+Cl2(g)COCl2(g)CO(g)+Cl2(g)COCl2(g)

Express your answers as signed integers. Enter the initial and the final oxidation states separated by a comma.

C:

O:

Cl:

3. 2NO(g)+Br2(g)2BrNO(g)

Express your answers as signed integers. Enter the initial and the final oxidation states separated by a comma.

N:

O:

Br:

4. H2(g)+CO2(g)H2O(g)+CO(g)

Express your answers as signed integers. Enter the initial and the final oxidation states separated by a comma.

H:

C:

O:

Explanation / Answer

1)

In SbCl5,

oxidation state of Cl = -1

oxidation state of Sb = +5

in SbCl3:

oxidation state of Cl = -1

oxidation state of Sb = +3

In Cl2:

oxidation state of Cl = 0

Oxidation state of Cl is changing from -1 to 0

So, Cl is oxidised

Oxidation state of Sb is changing from +5 to +3

So, Sb is reduced

Answer:

Sb: reduced

Cl: oxidised

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