Predict the normal boiling point of hydrogen peroxide (H2O2) from the following

ID: 692619 • Letter: P

Question

Predict the normal boiling point of hydrogen peroxide (H2O2) from the following data:

1st attempt

Part 1 (1 point)

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Predict the normal boiling point of hydrogen peroxide (H2O2) from the following data:

Part 2

A liquid, because its estimated boiling point is less than 25°C.

A gas, because its estimated boiling point is less than 25°C.

A gas, because its estimated boiling point is greater than 25°C.

A liquid, because its estimated boiling point is greater than 25°C.

Hºf, kJ/mol Sºf, J/(mol•K) H2O2(l) -187.8 110 H2O2(g) -136.3 233

H2O2(L) <---> H2O2(g)

DH0rxn = (DH0f,H2O2(g) - DH0f,H2O2(L))

= (-136.3-(-187.8))

= 51.5 Kj/mol

DS0rxn = (s0f,H2O2(g) - s0f,H2O2(L))

= (233 - 110)

= 123j/mol.k

at the boiling point(Tb), DG0 = 0 (due to equilibrium)

DG0 = DH0-TDS0

0 = 51.5*10^3 - (T*123)

T = boilingpoint of H2O2 = 418.7 K

= 418.7-273.15

= 145.55 c

PART 2

AS, boilingpoint of H2O2 is higher than room temperature(25 c). it is liquid.

answer: A liquid, because its estimated boiling point is greater than 25°C

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