G For the reaction 2NH34×NG 02H2O2O2H200.02 x shameless cvg.cengagenow.com/ilrn/

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G For the reaction 2NH34×NG 02H2O2O2H200.02 x shameless cvg.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locatorsassignment-take&tak; For the reaction CO2(9 × Use the References to aecess importast values if seeded for this quest For the reaction The standard free energy change for the reaction of 1.55 moles of NH() at 270 K 1 atm would be This reaction is (reactant, product) Assume that He and are independent of temperature. kJ. favored under standard conditions at 270 K Try Another Version 2 item attempts remaining Submit Answer

Explanation / Answer

deltaHo = -683.1 KJ

deltaSo = -365.6 J/K

= -0.3656 KJ/K

T = 270 K

we have below equation to be used:

deltaGo = deltaHo - T*deltaSo

deltaGo = -683.1 - 270.0 * -0.3656

deltaGo = -584.388 KJ

This is when 2 mol of NH3 is reacting as per question

for 1.55 moles of NH3, deltaGo = (-584.388 KJ)*1.55/2

= -453 KJ

Answer: -453 KJ

Since delta Go is negative, this is product favoured

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