9. (6 points) A pair of stereoisomers is shown to exist as a 65:35 mixture at eq

Question

9. (6 points) A pair of stereoisomers is shown to exist as a 65:35 mixture at equilibrium at 27° C. What is the difference in the heats of formation of these two stereoisomers? What will be the composition at +1200 C? At -100° C? [Assume that entropy changes may be ignored.] 10. (8 points) Suggest explanation(s) for the following experimental data. Compound A can be recovered unchanged after standing briefly in a solution of methanol containing a catalytic amount of sodium methoxide while compound B cannot be recovered as compound B. Provide the structure of the material isolated from the reaction of compound B with the sodium methoxide.

Explanation / Answer

Free energy dG is equal to dH in this case

dH = dG = -RTlnK

at,

T = 120 + 273 = 393 K

R = gas constant

K = 65/35

we get,

Difference in he Heat of formation = -8,314 x 393 ln(65/35)

                                                       = -2.023 kJ/mol

At T = -100 + 273 = 173 K

Difference in he Heat of formation = -8,314 x 173 ln(65/35)

                                                       = -0.890 kJ/mol

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