Computer 14A DATA ANALYSIS nown solution. Describe, in detail, how you Identify

Question

Computer 14A DATA ANALYSIS nown solution. Describe, in detail, how you Identify the cations that were present in your unk used the results of your testing to identify the contents of your unknown solution. As your concluding remarks, consider the following questions: 1. Describe the process by which Ag' ions are precipitated out of solution. disproportion reaction occurs when NH, solution reacts with Hg-C. Write a balanced reaction equation for this event. 3. Write half-reactions that show how H:0; can act as either an oxidizing agent or a reducing agent, and describe where each of these situations occurred in your testing. 4. In your testing, several precipitates are formed, and then dissolved as complexes. Select three of these situations for which to write a balanced reaction equation. When Mn2"ions are separated from the mixture, they go through a series of oxidizing and reducing steps. Write the reaction equations that describe this process. S. 6. The NHs solution is used, in three separate instances, to separate two ions. In each of these cases, one ion forms a precipitate and the other ion remains in solution as a complex Describe each of these instances, using reaction equations 7. Al and Zn2" ions are amphoteric. Describe how the amphoteric nature of these ions is shown in your testing. 14A -6 Advanced Chemistry with Vernier

Explanation / Answer

1) Let us take small portion of the solution, and add 6 M HCl drop wise. The reaction can takes place and a white precipitate will form. Let us pour a small amount of hot water to the precipitate. Still you find the white precipitate, and then it indicates that the Ag+ is precipitated from the solution.

2) Balanced disproportination reaction when NH3 solution reacts with Hg2Cl2 is given as:

Hg2Cl2 + 2NH3 Hg + HgNH2Cl + NH4Cl

Disproportination reaction is both oxidation and reduction is possible for one component.

If we observe clearly Hg+ is reduced to metallic mercury (with zero oxidation state), and Hg+ is oxidized to Hg2+.

3) Hydrogen peroxide has the ability to gain or lose electrons. The oxygen atoms in hydrogen peroxide are in the -1 oxidation state. By gaining an electron oxidation state changes from -1 to -2, and by losing electron oxidation state changes to zero.

2H2O2 O2+2H2O

Oxidation half reaction:                                               reduction half reaction:

H2O2 O2 + e-                                                            H2O2 + e- H2O

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