Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

6 of Map University Science Books presented by Sapling Learning General Chemistr

ID: 693360 • Letter: 6

Question

6 of Map University Science Books presented by Sapling Learning General Chemistry 4th Edition At noon on a clear day, sunlight reaches the earth's surface at Madison, Wisconsin, with an average approximately 9.00 kJs m2 It the sunlight consists of photons with an average wavel how many photons strike a 6.80 cm2 area per second? power of ength of 510.0 nm 1.49 x 103 photons s is View this feedback by clicking on the bar again to hide the divider bar. Click on the divider Incorrect O Previous Give Up & View Solution iPTryAgain0 Next Exit

Explanation / Answer

power of sunglight = 9 KJ s-1 m-2

area given = 6.8 cm2 = 6.8 x (10^-2) ^2 m2 = 0.00068 m2

Energy per 0.00068m2 per s-1 is given by E = Power x time x area = 9KJs-1m-2 x 1s x 0.00068m2

                       = 0.00612 KJ = 6.12 J

wavelength = 510 nm = 510 x 10^-9 m

frequency = ( speed of leight / wavelength) = ( 3 x 10^8 m/s) / ( 510 x 10^-9 m) = 5.88 x 10^14 s-1

Now energy = E== h x v = 6.625 x 10^-34 Js x 5.88 x 10^14 s-1 = 3.9 x 10^-19 J

Thus 1 photon energy = 3.9 x10^-19 J

Number of photons per s-1 = Total energy ./ energy per photon

            = ( 6.12 J s-1) / ( 3.9 x 10^-19 J)

         = 1.57 x 10^19 photons s-1

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote