lowing plot shows a titration curve for the titration of 1,00L of 1.00 M diproti

Question

lowing plot shows a titration curve for the titration of 1,00L of 1.00 M diprotic acid H2A 14 35) Which point a-d represents the second equivalence point? 35)-- A) point a B) point b C) point c D) point d 36) How many CI-ions are around each K* ion in KCl, which has a cubic unit cell with Cl- ions on each corner and each face? A) 1 B) 4 C)6 D)8 Which of the following are unstable with respect to their constituent elements at 25C? 37) C2H2() 227 CH3OH1-239 329 201 127 209 -166 A) C8H180)C2H2k) B) C2H2(8) D) CH3OH) 38) The decomposition of ammonia is:2 NH3(e) N2). 3 H2() If Kp is 15- 103 at 400°C what is 38) B) 22 10-7 atm C)44 106 atm 39) What is the identity of M in the hydrate M(0120)% that has the 0,10 M solution with the highest 39) the partial pressure of ammonia at equilibrium when N2 is 0.10 atm and H2 is 0.15 atm A) 2.1 103 atm D) 47 x 10-4 atm pH? A) Mg2+ B) Na* C) Li+ B-8

Explanation / Answer

35

2nd equivalence point --> must be the 2nd chang ein pH drastically

this is "D"

36

if there is Cl- ions on each corner and each face:

each corner --> 1/8*8 = 1 Cl- ion

each face = 1/2*6 = 3

total Cl- ions 0 1+3 = 4

Q38

in order to be "unstable" the dG vlau emust be positive, meaning that this is not favoured

from t elist

only C2H2 is not negative, so t is unstable

Q38

Kp = P-H2^3 * P-N2 / (P-NH3)^2

1.5*10^3 = (0.15^3)(0.1)/(P-NH3)^2

(P-NH3)^2 = ((0.15^3)(0.1))/(1.5*10^3 )

= (2.25*10^-7)^0.5 = 0.000474

choose D

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